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Power factor and correction capacitors — kW, kVA, kvar and capacitor sizing

What power factor is and why a low one raises current, sizing capacitors as kvar = kW × (tan φ1 − tan φ2) and in µF, cautions at motors, and reading meters.

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Power meters and plant data show numbers like «power factor 0.85». Power factor tells you how much extra current flows for the same work. Here is what it is, how capacitors raise it and how to size them.

kW, kvar, kVA and power factor

Cables, breakers and transformers are sized by current, so the same kW at a lower power factor needs bigger equipment. 100 kW at 400 V three-phase is 144 A at power factor 1, 180 A at 0.8 and 192 A at 0.75.

Motor power factor

According to ABB's Motor guide (§4.10), motor power factor is usually between 0.7 and 0.9, lower for small motors and higher for large ones. It also falls with load: in the same guide's table a motor rated at 0.85 has 0.81 at 3/4 load, 0.72 at 1/2 and 0.54 at 1/4. Installations with many motors therefore have a lower overall power factor, and ABB notes that power suppliers sometimes require it to be raised.

Raising the power factor with capacitors

Power triangle on a 100 kW base: before correction 88.2 kvar reactive and 133.3 kVA apparent; a 55.3 kvar capacitor reduces reactive power to 32.9 kvar and apparent power to 105.3 kVA
A 100 kW load from 0.75 to 0.95. The capacitor removes 55.3 kvar of reactive power; real power is unchanged.

A capacitor supplies reactive power opposite to a motor's, so connecting it in parallel reduces the reactive power drawn from the supply. ABB's Motor guide likewise describes raising the power factor by «connecting capacitors to the supply which absorb reactive power». Real power stays the same; only apparent power and current fall.

Qc (kvar) = P (kW) × (tan φ1 − tan φ2)
tan φ = √(1 − cos²φ) ÷ cos φ

100 kW, 0.75 → 0.95:  tan φ1 = 0.882, tan φ2 = 0.329
Qc = 100 × 0.553 = 55.3 kvar
Line current (three-phase 400 V): 192.5 A → 151.9 A

ABB Motor guide Table 4.7 tabulates tan φ1 − tan φ2 as a «constant K» (uncompensated 0.50–0.90 → compensated 0.80, 0.85, 0.90, 0.95). For a motor it uses Q = K × P ÷ η: the shaft output P divided by efficiency η gives the input power, multiplied by K.

kvar to µF

One capacitor: C = Q × 1000 ÷ (2π × f × U²)   [F]   (Q its kvar, U the voltage across it)

Three-phase delta: 3 capacitors, Qc ÷ 3 each, U = line voltage
Three-phase star:  3 capacitors, Qc ÷ 3 each, U = line voltage ÷ √3  → 3× the capacitance

55.3 kvar, 400 V, 50 Hz, delta: 18.4 kvar → about 367 µF × 3

ABB's Motor guide gives C = 3.2 × 10⁶ × Q ÷ U² at 50 Hz. 3.2 × 10⁶ is 10⁹ ÷ (2π × 50) ≈ 3.18 × 10⁶ rounded; with Q in kvar and U in volts the result is in µF. The same capacitor gives 1.2 times the kvar at 60 Hz as at 50 Hz, so match the frequency.

Cautions at the motor (ABB Motor guide §4.10)

Lagging, leading and the target

With current behind voltage, as in a motor, the power factor is lagging; with too much capacitance the current leads. The closer the target is to 1.0, the faster the kvar grows and the easier it is to go leading when the load drops. Plants with varying load often use automatic correction that switches several steps. Utility requirements and tariffs differ by contract, so check your supply agreement (we have not checked the original terms, so no figures here).

Reading power factor from a meter

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Published 2026-10-23